Nonlifts in S9(K(16))+ are old forms
The one nonlift eigenform in S9(K(16))+
must be the old form coming from the nonlift eigenform in
S9(K(8))−.
This already proves S9(K(16))+ has at least one nonlift eigenform
and hence Borcherds products are not needed to help span this Fricke eigenspace.