Nonlifts in S10(K(16))− are old forms
The two nonlift eigenforms in S10(K(16))−
must be the two old forms coming from the two nonlift eigenforms in
S10(K(8))+.
This already proves S9(K(16))+ has at least two nonlift eigenforms
and hence Borcherds products are not needed to help span this Fricke eigenspace.